Solve Using the Square Root Property (3x+1)^2=49

${(3 x + 1)}^{2} = 49$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$3 x + 1 = \pm \sqrt{49}$

Step 2

Simplify $\pm \sqrt{49}$ .

Rewrite $49$ as $7^{2}$ .

$3 x + 1 = \pm \sqrt{7^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$3 x + 1 = \pm 7$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$3 x + 1 = 7$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$3 x = 7 - 1$

Subtract $1$ from $7$ .

$3 x = 6$

Divide each term in $3 x = 6$ by $3$ and simplify.

Divide each term in $3 x = 6$ by $3$ .

$\frac{3 x}{3} = \frac{6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{6}{3}$

Divide $x$ by $1$ .

$x = \frac{6}{3}$

Simplify the right side.

Divide $6$ by $3$ .

$x = 2$

Next, use the negative value of the $\pm$ to find the second solution.

$3 x + 1 = - 7$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$3 x = - 7 - 1$

Subtract $1$ from $- 7$ .

$3 x = - 8$

Divide each term in $3 x = - 8$ by $3$ and simplify.

Divide each term in $3 x = - 8$ by $3$ .

$\frac{3 x}{3} = \frac{- 8}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{- 8}{3}$

Divide $x$ by $1$ .

$x = \frac{- 8}{3}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{8}{3}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 2, - \frac{8}{3}$

Solve Using the Square Root Property (3x+1)^2=49

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