Solve Using the Square Root Property 4x^2-4x+1=9

$4 x^{2} - 4 x + 1 = 9$

Step 1

Subtract $9$ from both sides of the equation.

$4 x^{2} - 4 x + 1 - 9 = 0$

Step 2

Subtract $9$ from $1$ .

$4 x^{2} - 4 x - 8 = 0$

Step 3

Factor the left side of the equation.

Factor $4$ out of $4 x^{2} - 4 x - 8$ .

Factor $4$ out of $4 x^{2}$ .

$4 (x^{2}) - 4 x - 8 = 0$

Factor $4$ out of $- 4 x$ .

$4 (x^{2}) + 4 (- x) - 8 = 0$

Factor $4$ out of $- 8$ .

$4 (x^{2}) + 4 (- x) + 4 (- 2) = 0$

Factor $4$ out of $4 (x^{2}) + 4 (- x)$ .

$4 (x^{2} - x) + 4 (- 2) = 0$

Factor $4$ out of $4 (x^{2} - x) + 4 (- 2)$ .

$4 (x^{2} - x - 2) = 0$

Factor.

Factor $x^{2} - x - 2$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 2$ and whose sum is $- 1$ .

$- 2, 1$

Write the factored form using these integers.

$4 ((x - 2) (x + 1)) = 0$

Remove unnecessary parentheses.

$4 (x - 2) (x + 1) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 2 = 0$

$x + 1 = 0$

Step 5

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

Step 6

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 7

The final solution is all the values that make $4 (x - 2) (x + 1) = 0$ true.

$x = 2, - 1$

Solve Using the Square Root Property 4x^2-4x+1=9

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