Solve Using the Square Root Property 5x^2+4=14

$5 x^{2} + 4 = 14$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$5 x^{2} = 14 - 4$

Subtract $4$ from $14$ .

$5 x^{2} = 10$

Step 2

Divide each term in $5 x^{2} = 10$ by $5$ and simplify.

Divide each term in $5 x^{2} = 10$ by $5$ .

$\frac{5 x^{2}}{5} = \frac{10}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x^{2}}{5} = \frac{10}{5}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{10}{5}$

Simplify the right side.

Divide $10$ by $5$ .

$x^{2} = 2$

Step 3

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{2}$

Step 4

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = \sqrt{2}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \sqrt{2}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \sqrt{2}, - \sqrt{2}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = \sqrt{2}, - \sqrt{2}$

Decimal Form:

$x = 1.41421356 \dots, - 1.41421356 \dots$