Solve Using the Square Root Property (7x-4)^2=16

${(7 x - 4)}^{2} = 16$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$7 x - 4 = \pm \sqrt{16}$

Step 2

Simplify $\pm \sqrt{16}$ .

Rewrite $16$ as $4^{2}$ .

$7 x - 4 = \pm \sqrt{4^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$7 x - 4 = \pm 4$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$7 x - 4 = 4$

Move all terms not containing $x$ to the right side of the equation.

Add $4$ to both sides of the equation.

$7 x = 4 + 4$

Add $4$ and $4$ .

$7 x = 8$

Divide each term in $7 x = 8$ by $7$ and simplify.

Divide each term in $7 x = 8$ by $7$ .

$\frac{7 x}{7} = \frac{8}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{8}{7}$

Divide $x$ by $1$ .

$x = \frac{8}{7}$

Next, use the negative value of the $\pm$ to find the second solution.

$7 x - 4 = - 4$

Move all terms not containing $x$ to the right side of the equation.

Add $4$ to both sides of the equation.

$7 x = - 4 + 4$

Add $- 4$ and $4$ .

$7 x = 0$

Divide each term in $7 x = 0$ by $7$ and simplify.

Divide each term in $7 x = 0$ by $7$ .

$\frac{7 x}{7} = \frac{0}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{0}{7}$

Divide $x$ by $1$ .

$x = \frac{0}{7}$

Simplify the right side.

Divide $0$ by $7$ .

$x = 0$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \frac{8}{7}, 0$

Solve Using the Square Root Property (7x-4)^2=16

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