Solve Using the Square Root Property 9y^2=4

$9 y^{2} = 4$

Step 1

Divide each term in $9 y^{2} = 4$ by $9$ and simplify.

Divide each term in $9 y^{2} = 4$ by $9$ .

$\frac{9 y^{2}}{9} = \frac{4}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 y^{2}}{9} = \frac{4}{9}$

Divide $y^{2}$ by $1$ .

$y^{2} = \frac{4}{9}$

Step 2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{\frac{4}{9}}$

Step 3

Simplify $\pm \sqrt{\frac{4}{9}}$ .

Rewrite $\sqrt{\frac{4}{9}}$ as $\frac{\sqrt{4}}{\sqrt{9}}$ .

$y = \pm \frac{\sqrt{4}}{\sqrt{9}}$

Simplify the numerator.

Rewrite $4$ as $2^{2}$ .

$y = \pm \frac{\sqrt{2^{2}}}{\sqrt{9}}$

Pull terms out from under the radical, assuming positive real numbers.

$y = \pm \frac{2}{\sqrt{9}}$

Simplify the denominator.

Rewrite $9$ as $3^{2}$ .

$y = \pm \frac{2}{\sqrt{3^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$y = \pm \frac{2}{3}$

Step 4

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$y = \frac{2}{3}$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - \frac{2}{3}$

The complete solution is the result of both the positive and negative portions of the solution.

$y = \frac{2}{3}, - \frac{2}{3}$