Solve Using the Square Root Property x^2-14x+49=49

$x^{2} - 14 x + 49 = 49$

Step 1

Subtract $49$ from both sides of the equation.

$x^{2} - 14 x + 49 - 49 = 0$

Step 2

Combine the opposite terms in $x^{2} - 14 x + 49 - 49$ .

Subtract $49$ from $49$ .

$x^{2} - 14 x + 0 = 0$

Add $x^{2} - 14 x$ and $0$ .

$x^{2} - 14 x = 0$

Step 3

Factor $x$ out of $x^{2} - 14 x$ .

Factor $x$ out of $x^{2}$ .

$x \cdot x - 14 x = 0$

Factor $x$ out of $- 14 x$ .

$x \cdot x + x \cdot - 14 = 0$

Factor $x$ out of $x \cdot x + x \cdot - 14$ .

$x (x - 14) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x - 14 = 0$

Step 5

Set $x$ equal to $0$ .

$x = 0$

Step 6

Set $x - 14$ equal to $0$ and solve for $x$ .

Set $x - 14$ equal to $0$ .

$x - 14 = 0$

Add $14$ to both sides of the equation.

$x = 14$

Step 7

The final solution is all the values that make $x (x - 14) = 0$ true.

$x = 0, 14$