Solve Using the Square Root Property (x+2)^2=-14

${(x + 2)}^{2} = - 14$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x + 2 = \pm \sqrt{- 14}$

Step 2

Simplify $\pm \sqrt{- 14}$ .

Rewrite $- 14$ as $- 1 (14)$ .

$x + 2 = \pm \sqrt{- 1 (14)}$

Rewrite $\sqrt{- 1 (14)}$ as $\sqrt{- 1} \cdot \sqrt{14}$ .

$x + 2 = \pm \sqrt{- 1} \cdot \sqrt{14}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x + 2 = \pm i \sqrt{14}$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x + 2 = i \sqrt{14}$

Subtract $2$ from both sides of the equation.

$x = i \sqrt{14} - 2$

Next, use the negative value of the $\pm$ to find the second solution.

$x + 2 = - i \sqrt{14}$

Subtract $2$ from both sides of the equation.

$x = - i \sqrt{14} - 2$

The complete solution is the result of both the positive and negative portions of the solution.

$x = i \sqrt{14} - 2, - i \sqrt{14} - 2$