Solve Using the Square Root Property x^2+4x+4=1

$x^{2} + 4 x + 4 = 1$

Step 1

Subtract $1$ from both sides of the equation.

$x^{2} + 4 x + 4 - 1 = 0$

Step 2

Subtract $1$ from $4$ .

$x^{2} + 4 x + 3 = 0$

Step 3

Factor $x^{2} + 4 x + 3$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $3$ and whose sum is $4$ .

$1, 3$

Write the factored form using these integers.

$(x + 1) (x + 3) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 1 = 0$

$x + 3 = 0$

Step 5

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 6

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

Step 7

The final solution is all the values that make $(x + 1) (x + 3) = 0$ true.

$x = - 1, - 3$

Solve Using the Square Root Property x^2+4x+4=1

Related Questions

Support LCMGCF.com by disabling your adblocker.