Solve Using the Square Root Property x^2+6=15

$x^{2} + 6 = 15$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$x^{2} = 15 - 6$

Subtract $6$ from $15$ .

$x^{2} = 9$

Step 2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{9}$

Step 3

Simplify $\pm \sqrt{9}$ .

Rewrite $9$ as $3^{2}$ .

$x = \pm \sqrt{3^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 3$

Step 4

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 3$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 3$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 3, - 3$