Solve Using the Square Root Property (x-3)^2-16=0

${(x - 3)}^{2} - 16 = 0$

Step 1

Add $16$ to both sides of the equation.

${(x - 3)}^{2} = 16$

Step 2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x - 3 = \pm \sqrt{16}$

Step 3

Simplify $\pm \sqrt{16}$ .

Rewrite $16$ as $4^{2}$ .

$x - 3 = \pm \sqrt{4^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x - 3 = \pm 4$

Step 4

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x - 3 = 4$

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$x = 4 + 3$

Add $4$ and $3$ .

$x = 7$

Next, use the negative value of the $\pm$ to find the second solution.

$x - 3 = - 4$

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$x = - 4 + 3$

Add $- 4$ and $3$ .

$x = - 1$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 7, - 1$