Solve Using the Square Root Property (x-4)^2=27

${(x - 4)}^{2} = 27$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x - 4 = \pm \sqrt{27}$

Step 2

Simplify $\pm \sqrt{27}$ .

Rewrite $27$ as $3^{2} \cdot 3$ .

Factor $9$ out of $27$ .

$x - 4 = \pm \sqrt{9 (3)}$

Rewrite $9$ as $3^{2}$ .

$x - 4 = \pm \sqrt{3^{2} \cdot 3}$

Pull terms out from under the radical.

$x - 4 = \pm 3 \sqrt{3}$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x - 4 = 3 \sqrt{3}$

Add $4$ to both sides of the equation.

$x = 3 \sqrt{3} + 4$

Next, use the negative value of the $\pm$ to find the second solution.

$x - 4 = - 3 \sqrt{3}$

Add $4$ to both sides of the equation.

$x = - 3 \sqrt{3} + 4$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 3 \sqrt{3} + 4, - 3 \sqrt{3} + 4$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = 3 \sqrt{3} + 4, - 3 \sqrt{3} + 4$

Decimal Form:

$x = 9.19615242 \dots, - 1.19615242 \dots$