Solve Using the Square Root Property (x+4)^2=49

${(x + 4)}^{2} = 49$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x + 4 = \pm \sqrt{49}$

Step 2

Simplify $\pm \sqrt{49}$ .

Rewrite $49$ as $7^{2}$ .

$x + 4 = \pm \sqrt{7^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x + 4 = \pm 7$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x + 4 = 7$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$x = 7 - 4$

Subtract $4$ from $7$ .

$x = 3$

Next, use the negative value of the $\pm$ to find the second solution.

$x + 4 = - 7$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$x = - 7 - 4$

Subtract $4$ from $- 7$ .

$x = - 11$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 3, - 11$