Solve Using the Square Root Property y^2=16

$y^{2} = 16$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{16}$

Step 2

Simplify $\pm \sqrt{16}$ .

Rewrite $16$ as $4^{2}$ .

$y = \pm \sqrt{4^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$y = \pm 4$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$y = 4$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - 4$

The complete solution is the result of both the positive and negative portions of the solution.

$y = 4, - 4$