Solve Using the Square Root Property y^2=36

$y^{2} = 36$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{36}$

Simplify $\pm \sqrt{36}$ .

Rewrite $36$ as $6^{2}$ .

$y = \pm \sqrt{6^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$y = \pm 6$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$y = 6$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - 6$

The complete solution is the result of both the positive and negative portions of the solution.

$y = 6, - 6$