Use the Rational Roots Test to Find All Possible Roots 10x^3-7x^2+x-10=0

$10 x^{3} - 7 x^{2} + x - 10 = 0$

Step 1

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 2, \pm 5, \pm 10$

$q = \pm 1, \pm 2, \pm 5, \pm 10$

Step 2

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm \frac{1}{2}, \pm \frac{1}{5}, \pm \frac{1}{10}, \pm 2, \pm \frac{2}{5}, \pm 5, \pm \frac{5}{2}, \pm 10$

Use the Rational Roots Test to Find All Possible Roots 10x^3-7x^2+x-10=0

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