Use the Rational Roots Test to Find All Possible Roots 12x^3-91x^2+50x-7=0

$12 x^{3} - 91 x^{2} + 50 x - 7 = 0$

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 7$

$q = \pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm 12$

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm \frac{1}{2}, \pm \frac{1}{3}, \pm \frac{1}{4}, \pm \frac{1}{6}, \pm \frac{1}{12}, \pm 7, \pm \frac{7}{2}, \pm \frac{7}{3}, \pm \frac{7}{4}, \pm \frac{7}{6}, \pm \frac{7}{12}$

Use the Rational Roots Test to Find All Possible Roots 12x^3-91x^2+50x-7=0

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