Use the Rational Roots Test to Find All Possible Roots 9x^3+5x^2-6x-4=0

$9 x^{3} + 5 x^{2} - 6 x - 4 = 0$

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 2, \pm 4$

$q = \pm 1, \pm 3, \pm 9$

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm \frac{1}{3}, \pm \frac{1}{9}, \pm 2, \pm \frac{2}{3}, \pm \frac{2}{9}, \pm 4, \pm \frac{4}{3}, \pm \frac{4}{9}$

Use the Rational Roots Test to Find All Possible Roots 9x^3+5x^2-6x-4=0

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