Use the Rational Roots Test to Find All Possible Roots x^3-4x^2+7x-8=0

$x^{3} - 4 x^{2} + 7 x - 8 = 0$

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 2, \pm 4, \pm 8$

$q = \pm 1$

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm 2, \pm 4, \pm 8$

Use the Rational Roots Test to Find All Possible Roots x^3-4x^2+7x-8=0

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