Write as a Function of v -2u+6v=9

$- 2 u + 6 v = 9$

Step 1

Subtract $6 v$ from both sides of the equation.

$- 2 u = 9 - 6 v$

Step 2

Divide each term in $- 2 u = 9 - 6 v$ by $- 2$ and simplify.

Divide each term in $- 2 u = 9 - 6 v$ by $- 2$ .

$\frac{- 2 u}{- 2} = \frac{9}{- 2} + \frac{- 6 v}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 u}{- 2} = \frac{9}{- 2} + \frac{- 6 v}{- 2}$

Divide $u$ by $1$ .

$u = \frac{9}{- 2} + \frac{- 6 v}{- 2}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$u = - \frac{9}{2} + \frac{- 6 v}{- 2}$

Cancel the common factor of $- 6$ and $- 2$ .

Factor $- 2$ out of $- 6 v$ .

$u = - \frac{9}{2} + \frac{- 2 (3 v)}{- 2}$

Cancel the common factors.

Factor $- 2$ out of $- 2$ .

$u = - \frac{9}{2} + \frac{- 2 (3 v)}{- 2 (1)}$

Cancel the common factor.

$u = - \frac{9}{2} + \frac{- 2 (3 v)}{- 2 \cdot 1}$

Rewrite the expression.

$u = - \frac{9}{2} + \frac{3 v}{1}$

Divide $3 v$ by $1$ .

$u = - \frac{9}{2} + 3 v$

Step 3

To rewrite as a function of $v$ , write the equation so that $u$ is by itself on one side of the equal sign and an expression involving only $v$ is on the other side.

$f (v) = - \frac{9}{2} + 3 v$

Write as a Function of v -2u+6v=9

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