Write as a Function of x 9x^2-kx+25=0

$9 x^{2} - k x + 25 = 0$

Step 1

Move all terms not containing $k$ to the right side of the equation.

Subtract $9 x^{2}$ from both sides of the equation.

$- k x + 25 = - 9 x^{2}$

Subtract $25$ from both sides of the equation.

$- k x = - 9 x^{2} - 25$

Step 2

Divide each term in $- k x = - 9 x^{2} - 25$ by $- 1 x$ and simplify.

Divide each term in $- k x = - 9 x^{2} - 25$ by $- 1 x$ .

$\frac{- k x}{- 1 x} = \frac{- 9 x^{2}}{- 1 x} + \frac{- 25}{- 1 x}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{k x}{x} = \frac{- 9 x^{2}}{- 1 x} + \frac{- 25}{- 1 x}$

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{k x}{x} = \frac{- 9 x^{2}}{- 1 x} + \frac{- 25}{- 1 x}$

Divide $k$ by $1$ .

$k = \frac{- 9 x^{2}}{- 1 x} + \frac{- 25}{- 1 x}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $x^{2}$ and $x$ .

Factor $x$ out of $- 9 x^{2}$ .

$k = \frac{x (- 9 x)}{- 1 x} + \frac{- 25}{- 1 x}$

Move the negative one from the denominator of $\frac{- 9 x}{- 1}$ .

$k = - 1 \cdot (- 9 x) + \frac{- 25}{- 1 x}$

Rewrite $- 1 \cdot (- 9 x)$ as $- (- 9 x)$ .

$k = - (- 9 x) + \frac{- 25}{- 1 x}$

Multiply $- 9$ by $- 1$ .

$k = 9 x + \frac{- 25}{- 1 x}$

Dividing two negative values results in a positive value.

$k = 9 x + \frac{25}{x}$

Step 3

To rewrite as a function of $x$ , write the equation so that $k$ is by itself on one side of the equal sign and an expression involving only $x$ is on the other side.

$f (x) = 9 x + \frac{25}{x}$

Write as a Function of x 9x^2-kx+25=0

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