Write as a Function of x square root of 1-x-3y=-3

$\sqrt{1 - x} - 3 y = - 3$

Step 1

Subtract $\sqrt{1 - x}$ from both sides of the equation.

$- 3 y = - 3 - \sqrt{1 - x}$

Step 2

Divide each term in $- 3 y = - 3 - \sqrt{1 - x}$ by $- 3$ and simplify.

Divide each term in $- 3 y = - 3 - \sqrt{1 - x}$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 3}{- 3} + \frac{- \sqrt{1 - x}}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 3}{- 3} + \frac{- \sqrt{1 - x}}{- 3}$

Divide $y$ by $1$ .

$y = \frac{- 3}{- 3} + \frac{- \sqrt{1 - x}}{- 3}$

Simplify the right side.

Simplify each term.

Divide $- 3$ by $- 3$ .

$y = 1 + \frac{- \sqrt{1 - x}}{- 3}$

Dividing two negative values results in a positive value.

$y = 1 + \frac{\sqrt{1 - x}}{3}$

Combine into one fraction.

Write $1$ as a fraction with a common denominator.

$y = \frac{3}{3} + \frac{\sqrt{1 - x}}{3}$

Combine the numerators over the common denominator.

$y = \frac{3 + \sqrt{1 - x}}{3}$

Step 3

To rewrite as a function of $x$ , write the equation so that $y$ is by itself on one side of the equal sign and an expression involving only $x$ is on the other side.

$f (x) = \frac{3 + \sqrt{1 - x}}{3}$

Write as a Function of x square root of 1-x-3y=-3

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