Write as a Set of Linear Factors f(x)=x^3+11x^2+23x-35

$f (x) = x^{3} + 11 x^{2} + 23 x - 35$

Step 1

Factor $x^{3} + 11 x^{2} + 23 x - 35$ using the rational roots test.

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$f (x) = p = \pm 1, \pm 35, \pm 5, \pm 7$

$q = \pm 1$

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$f (x) = \pm 1, \pm 35, \pm 5, \pm 7$

Substitute $1$ and simplify the expression. In this case, the expression is equal to $0$ so $1$ is a root of the polynomial.

Substitute $1$ into the polynomial.

$f (x) = 1^{3} + 11 \cdot 1^{2} + 23 \cdot 1 - 35$

Raise $1$ to the power of $3$ .

$f (x) = 1 + 11 \cdot 1^{2} + 23 \cdot 1 - 35$

Raise $1$ to the power of $2$ .

$f (x) = 1 + 11 \cdot 1 + 23 \cdot 1 - 35$

Multiply $11$ by $1$ .

$f (x) = 1 + 11 + 23 \cdot 1 - 35$

Add $1$ and $11$ .

$f (x) = 12 + 23 \cdot 1 - 35$

Multiply $23$ by $1$ .

$f (x) = 12 + 23 - 35$

Add $12$ and $23$ .

$f (x) = 35 - 35$

Subtract $35$ from $35$ .

$f (x) = 0$

Since $1$ is a known root, divide the polynomial by $x - 1$ to find the quotient polynomial. This polynomial can then be used to find the remaining roots.

$f (x) = \frac{x^{3} + 11 x^{2} + 23 x - 35}{x - 1}$

Divide $x^{3} + 11 x^{2} + 23 x - 35$ by $x - 1$ .

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$f (x) =$

Divide the highest order term in the dividend $x^{3}$ by the highest order term in divisor $x$ .

$f (x) =$

Multiply the new quotient term by the divisor.

$f (x) =$

The expression needs to be subtracted from the dividend, so change all the signs in $x^{3} - x^{2}$

$f (x) =$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$f (x) =$

Pull the next terms from the original dividend down into the current dividend.

$f (x) =$

Divide the highest order term in the dividend $12 x^{2}$ by the highest order term in divisor $x$ .

$f (x) =$

Multiply the new quotient term by the divisor.

$f (x) =$

The expression needs to be subtracted from the dividend, so change all the signs in $12 x^{2} - 12 x$

$f (x) =$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$f (x) =$

Pull the next terms from the original dividend down into the current dividend.

$f (x) =$

Divide the highest order term in the dividend $35 x$ by the highest order term in divisor $x$ .

$f (x) =$

Multiply the new quotient term by the divisor.

$f (x) =$

The expression needs to be subtracted from the dividend, so change all the signs in $35 x - 35$

$f (x) =$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$f (x) =$

Since the remander is $0$ , the final answer is the quotient.

$f (x) = x^{2} + 12 x + 35$

Write $x^{3} + 11 x^{2} + 23 x - 35$ as a set of factors.

$f (x) = (x - 1) (x^{2} + 12 x + 35)$

Step 2

Factor $x^{2} + 12 x + 35$ using the AC method.

Consider the form $x^{2} + i x + c$ . Find a pair of integers whose product is $c$ and whose sum is $i$ . In this case, whose product is $35$ and whose sum is $12$ .

$f (x) = 5, 7$

Write the factored form using these integers.

$f (x) = (x - 1) ((x + 5) (x + 7))$

Remove unnecessary parentheses.

$f (x) = (x - 1) (x + 5) (x + 7)$

Write as a Set of Linear Factors f(x)=x^3+11x^2+23x-35

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