Write as a Set of Linear Factors x2/3-x1/3+4=6

$x \frac{2}{3} - x \frac{1}{3} + 4 = 6$

Subtract $6$ from both sides of the equation.

$x \frac{2}{3} - x \frac{1}{3} + 4 - 6 = 0$

Simplify $x \frac{2}{3} - x \frac{1}{3} + 4 - 6$ .

Simplify each term.

Combine $x$ and $\frac{2}{3}$ .

$\frac{x \cdot 2}{3} - x \frac{1}{3} + 4 - 6 = 0$

Move $2$ to the left of $x$ .

$\frac{2 \cdot x}{3} - x \frac{1}{3} + 4 - 6 = 0$

Combine $\frac{1}{3}$ and $x$ .

$\frac{2 x}{3} - \frac{x}{3} + 4 - 6 = 0$

Combine the numerators over the common denominator.

$4 - 6 + \frac{2 x - x}{3} = 0$

Subtract $x$ from $2 x$ .

$4 - 6 + \frac{x}{3} = 0$

Subtract $6$ from $4$ .

$- 2 + \frac{x}{3} = 0$