Write as a Single Logarithm 3* log base 2 of 4- log base 2 of 32

$3 \cdot \log_{2} (4) - \log_{2} (32)$

Step 1

Simplify each term.

Logarithm base $2$ of $4$ is $2$ .

$3 \cdot 2 - \log_{2} (32)$

Multiply $3$ by $2$ .

$6 - \log_{2} (32)$

Logarithm base $2$ of $32$ is $5$ .

$6 - 1 \cdot 5$

Multiply $- 1$ by $5$ .

$6 - 5$

Step 2

Subtract $5$ from $6$ .

$1$