Write as a Single Logarithm 4 log base 3 of x+ log base 3 of 7

$4 \log_{3} (x) + \log_{3} (7)$

Simplify $4 \log_{3} (x)$ by moving $4$ inside the logarithm.

$\log_{3} (x^{4}) + \log_{3} (7)$

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{3} (x^{4} \cdot 7)$

Move $7$ to the left of $x^{4}$ .

$\log_{3} (7 x^{4})$