Write as a Single Logarithm log base 4 of 5x+ log base 4 of 3x

$\log_{4} (5 x) + \log_{4} (3 x)$

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{4} (5 x (3 x))$

Rewrite using the commutative property of multiplication.

$\log_{4} (5 \cdot 3 x \cdot x)$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$\log_{4} (5 \cdot 3 (x \cdot x))$

Multiply $x$ by $x$ .

$\log_{4} (5 \cdot 3 x^{2})$

Multiply $5$ by $3$ .

$\log_{4} (15 x^{2})$