Write as a Single Logarithm log base 8 of 2+ log base 8 of 32

$\log_{8} (2) + \log_{8} (32)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{8} (2 \cdot 32)$

Step 2

Multiply $2$ by $32$ .

$\log_{8} (64)$

Step 3

Logarithm base $8$ of $64$ is $2$ .

$2$