Write as a Single Logarithm log base b of 8-3 log base b of 2

$\log_{b} (8) - 3 \log_{b} (2)$

Simplify each term.

Simplify $- 3 \log_{b} (2)$ by moving $3$ inside the logarithm.

$\log_{b} (8) - \log_{b} (2^{3})$

Raise $2$ to the power of $3$ .

$\log_{b} (8) - \log_{b} (8)$

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\log_{b} (\frac{8}{8})$

Divide $8$ by $8$ .

$\log_{b} (1)$

Logarithm base $b$ of $1$ is $0$ .

$0$