Write in Exponential Form log base 16 of 256=2

$\log_{16} (256) = 2$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 16$ , $x = 256$ , and $y = 2$ .