Write in Exponential Form log base 2 of 1/8=-3

$\log_{2} (\frac{1}{8}) = - 3$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 2$ , $x = \frac{1}{8}$ , and $y = - 3$ .