Write in Exponential Form log base 2 of 64=6

$\log_{2} (64) = 6$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 2$ , $x = 64$ , and $y = 6$ .