Write in Exponential Form log base 3 of 1/9=-2

$\log_{3} (\frac{1}{9}) = - 2$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 3$ , $x = \frac{1}{9}$ , and $y = - 2$ .