Write in Exponential Form log base 49 of 7=1/2

$\log_{49} (7) = \frac{1}{2}$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 49$ , $x = 7$ , and $y = \frac{1}{2}$ .

$b = 49$

$x = 7$

$y = \frac{1}{2}$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$49^{\frac{1}{2}} = 7$

Write in Exponential Form log base 49 of 7=1/2

Related Questions

Support LCMGCF.com by disabling your adblocker.