Write in Exponential Form log base 5 of 25=2

$\log_{5} (25) = 2$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 5$ , $x = 25$ , and $y = 2$ .

$b = 5$