Write in Exponential Form log base 5x of x=7/2

$\log_{5 x} (x) = \frac{7}{2}$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 5 x$ , $x = x$ , and $y = \frac{7}{2}$ .

$b = 5 x$

$x = x$

$y = \frac{7}{2}$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$5 x^{\frac{7}{2}} = x$

Write in Exponential Form log base 5x of x=7/2

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