Write in Exponential Form log base 6 of 1=0

$\log_{6} (1) = 0$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 6$ , $x = 1$ , and $y = 0$ .

$b = 6$