Write in Exponential Form log base 7 of 1/7=-1

$\log_{7} (\frac{1}{7}) = - 1$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 7$ , $x = \frac{1}{7}$ , and $y = - 1$ .