Write in Exponential Form log base 8 of 64=2

$\log_{8} (64) = 2$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 8$ , $x = 64$ , and $y = 2$ .