Write in Exponential Form log base 8 of 8=1

$\log_{8} (8) = 1$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 8$ , $x = 8$ , and $y = 1$ .

$b = 8$