Write in Exponential Form log base (x-2) of 5x+7=2

$\log_{(x - 2)} (5 x + 7) = 2$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = x - 2$ , $x = 5 x + 7$ , and $y = 2$ .

$b = x - 2$