Write in Exponential Form log base (x-2) of x^2-4x-6=4/5

$\log_{(x - 2)} (x^{2} - 4 x - 6) = \frac{4}{5}$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = x - 2$ , $x = x^{2} - 4 x - 6$ , and $y = \frac{4}{5}$ .

$b = x - 2$

$x = x^{2} - 4 x - 6$

$y = \frac{4}{5}$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

${(x - 2)}^{\frac{4}{5}} = x^{2} - 4 x - 6$

Write in Exponential Form log base (x-2) of x^2-4x-6=4/5

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