Write in Exponential Form log base (x+3) of 8=1/2

$\log_{(x + 3)} (8) = \frac{1}{2}$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = x + 3$ , $x = 8$ , and $y = \frac{1}{2}$ .

$b = x + 3$

$x = 8$

$y = \frac{1}{2}$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

${(x + 3)}^{\frac{1}{2}} = 8$

Write in Exponential Form log base (x+3) of 8=1/2

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