Write in Exponential Form log base (x-5) of 4x-6=2

$\log_{(x - 5)} (4 x - 6) = 2$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = x - 5$ , $x = 4 x - 6$ , and $y = 2$ .