Write in Exponential Form log base (x+8) of 8=2x

$\log_{(x + 8)} (8) = 2 x$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = x + 8$ , $x = 8$ , and $y = 2 x$ .

$b = x + 8$