Write in Exponential Form log base (x-8) of x=2x

$\log_{(x - 8)} (x) = 2 x$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = x - 8$ , $x = x$ , and $y = 2 x$ .