Write in Slope-Intercept Form (-1,3) and (-3,1)

$(- 1, 3)$ and $(- 3, 1)$

Find the slope of the line between $(- 1, 3)$ and $(- 3, 1)$ using $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ , which is the change of $y$ over the change of $x$ .

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{1 - (3)}{- 3 - (- 1)}$

Simplify.

Simplify the numerator.

Multiply $- 1$ by $3$ .

$m = \frac{1 - 3}{- 3 - (- 1)}$

Subtract $3$ from $1$ .

$m = \frac{- 2}{- 3 - (- 1)}$

Simplify the denominator.

Multiply $- 1$ by $- 1$ .

$m = \frac{- 2}{- 3 + 1}$

Add $- 3$ and $1$ .

$m = \frac{- 2}{- 2}$

Divide $- 2$ by $- 2$ .

$m = 1$

Use the slope $1$ and a given point $(- 1, 3)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (3) = 1 \cdot (x - (- 1))$

Simplify the equation and keep it in point-slope form.

$y - 3 = 1 \cdot (x + 1)$

Solve for $y$ .

Multiply $x + 1$ by $1$ .

$y - 3 = x + 1$

Move all terms not containing $y$ to the right side of the equation.

Add $3$ to both sides of the equation.

$y = x + 1 + 3$

Add $1$ and $3$ .

$y = x + 4$

Write in Slope-Intercept Form (-1,3) and (-3,1)

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