Write in Slope-Intercept Form (3,3) and (1,-3)

$(3, 3)$ and $(1, - 3)$

Find the slope of the line between $(3, 3)$ and $(1, - 3)$ using $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ , which is the change of $y$ over the change of $x$ .

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 3 - (3)}{1 - (3)}$

Simplify.

Simplify the numerator.

Multiply $- 1$ by $3$ .

$m = \frac{- 3 - 3}{1 - (3)}$

Subtract $3$ from $- 3$ .

$m = \frac{- 6}{1 - (3)}$

Simplify the denominator.

Multiply $- 1$ by $3$ .

$m = \frac{- 6}{1 - 3}$

Subtract $3$ from $1$ .

$m = \frac{- 6}{- 2}$

Divide $- 6$ by $- 2$ .

$m = 3$

Use the slope $3$ and a given point $(3, 3)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (3) = 3 \cdot (x - (3))$

Simplify the equation and keep it in point-slope form.

$y - 3 = 3 \cdot (x - 3)$

Solve for $y$ .

Simplify $3 \cdot (x - 3)$ .

Rewrite.

$y - 3 = 0 + 0 + 3 \cdot (x - 3)$

Simplify by adding zeros.

$y - 3 = 3 \cdot (x - 3)$

Apply the distributive property.

$y - 3 = 3 x + 3 \cdot - 3$

Multiply $3$ by $- 3$ .

$y - 3 = 3 x - 9$

Move all terms not containing $y$ to the right side of the equation.

Add $3$ to both sides of the equation.

$y = 3 x - 9 + 3$

Add $- 9$ and $3$ .

$y = 3 x - 6$

Write in Slope-Intercept Form (3,3) and (1,-3)

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