Write in Slope-Intercept Form (6,2) and (-3,-7)

$(6, 2)$ and $(- 3, - 7)$

Step 1

Find the slope of the line between $(6, 2)$ and $(- 3, - 7)$ using $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ , which is the change of $y$ over the change of $x$ .

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 7 - (2)}{- 3 - (6)}$

Simplify.

Simplify the numerator.

Multiply $- 1$ by $2$ .

$m = \frac{- 7 - 2}{- 3 - (6)}$

Subtract $2$ from $- 7$ .

$m = \frac{- 9}{- 3 - (6)}$

Simplify the denominator.

Multiply $- 1$ by $6$ .

$m = \frac{- 9}{- 3 - 6}$

Subtract $6$ from $- 3$ .

$m = \frac{- 9}{- 9}$

Divide $- 9$ by $- 9$ .

$m = 1$

Step 2

Use the slope $1$ and a given point $(6, 2)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (2) = 1 \cdot (x - (6))$

Step 3

Simplify the equation and keep it in point-slope form.

$y - 2 = 1 \cdot (x - 6)$

Step 4

Solve for $y$ .

Multiply $x - 6$ by $1$ .

$y - 2 = x - 6$

Move all terms not containing $y$ to the right side of the equation.

Add $2$ to both sides of the equation.

$y = x - 6 + 2$

Add $- 6$ and $2$ .

$y = x - 4$

Step 5

Write in Slope-Intercept Form (6,2) and (-3,-7)

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