Write in Standard Form (11b^2-4b+7)-(b^2+8b-9)

$(11 b^{2} - 4 b + 7) - (b^{2} + 8 b - 9)$

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c$

Simplify each term.

Apply the distributive property.

$11 b^{2} - 4 b + 7 - b^{2} - (8 b) - - 9$

Simplify.

Multiply $8$ by $- 1$ .

$11 b^{2} - 4 b + 7 - b^{2} - 8 b - - 9$

Multiply $- 1$ by $- 9$ .

$11 b^{2} - 4 b + 7 - b^{2} - 8 b + 9$

Simplify by adding terms.

Subtract $b^{2}$ from $11 b^{2}$ .

$10 b^{2} - 4 b + 7 - 8 b + 9$

Subtract $8 b$ from $- 4 b$ .

$10 b^{2} - 12 b + 7 + 9$

Add $7$ and $9$ .

$10 b^{2} - 12 b + 16$