Write in Standard Form (13-i)/(3-i)

$\frac{13 - i}{3 - i}$

Step 1

Multiply the numerator and denominator of $\frac{13 - i}{3 - i}$ by the conjugate of $3 - i$ to make the denominator real.

$\frac{13 - i}{3 - i} \cdot \frac{3 + i}{3 + i}$

Step 2

Multiply.

Combine.

$\frac{(13 - i) (3 + i)}{(3 - i) (3 + i)}$

Simplify the numerator.

Expand $(13 - i) (3 + i)$ using the FOIL Method.

Apply the distributive property.

$\frac{13 (3 + i) - i (3 + i)}{(3 - i) (3 + i)}$

Apply the distributive property.

$\frac{13 \cdot 3 + 13 i - i (3 + i)}{(3 - i) (3 + i)}$

Apply the distributive property.

$\frac{13 \cdot 3 + 13 i - i \cdot 3 - i i}{(3 - i) (3 + i)}$

Simplify and combine like terms.

Simplify each term.

Multiply $13$ by $3$ .

$\frac{39 + 13 i - i \cdot 3 - i i}{(3 - i) (3 + i)}$

Multiply $3$ by $- 1$ .

$\frac{39 + 13 i - 3 i - i i}{(3 - i) (3 + i)}$

Multiply $- i i$ .

Raise $i$ to the power of $1$ .

$\frac{39 + 13 i - 3 i - (i^{1} i)}{(3 - i) (3 + i)}$

Raise $i$ to the power of $1$ .

$\frac{39 + 13 i - 3 i - (i^{1} i^{1})}{(3 - i) (3 + i)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{39 + 13 i - 3 i - i^{1 + 1}}{(3 - i) (3 + i)}$

Add $1$ and $1$ .

$\frac{39 + 13 i - 3 i - i^{2}}{(3 - i) (3 + i)}$

Rewrite $i^{2}$ as $- 1$ .

$\frac{39 + 13 i - 3 i - - 1}{(3 - i) (3 + i)}$

Multiply $- 1$ by $- 1$ .

$\frac{39 + 13 i - 3 i + 1}{(3 - i) (3 + i)}$

Add $39$ and $1$ .

$\frac{40 + 13 i - 3 i}{(3 - i) (3 + i)}$

Subtract $3 i$ from $13 i$ .

$\frac{40 + 10 i}{(3 - i) (3 + i)}$

Simplify the denominator.

Expand $(3 - i) (3 + i)$ using the FOIL Method.

Apply the distributive property.

$\frac{40 + 10 i}{3 (3 + i) - i (3 + i)}$

Apply the distributive property.

$\frac{40 + 10 i}{3 \cdot 3 + 3 i - i (3 + i)}$

Apply the distributive property.

$\frac{40 + 10 i}{3 \cdot 3 + 3 i - i \cdot 3 - i i}$

Simplify.

Multiply $3$ by $3$ .

$\frac{40 + 10 i}{9 + 3 i - i \cdot 3 - i i}$

Multiply $3$ by $- 1$ .

$\frac{40 + 10 i}{9 + 3 i - 3 i - i i}$

Raise $i$ to the power of $1$ .

$\frac{40 + 10 i}{9 + 3 i - 3 i - (i^{1} i)}$

Raise $i$ to the power of $1$ .

$\frac{40 + 10 i}{9 + 3 i - 3 i - (i^{1} i^{1})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{40 + 10 i}{9 + 3 i - 3 i - i^{1 + 1}}$

Add $1$ and $1$ .

$\frac{40 + 10 i}{9 + 3 i - 3 i - i^{2}}$

Subtract $3 i$ from $3 i$ .

$\frac{40 + 10 i}{9 + 0 - i^{2}}$

Add $9$ and $0$ .

$\frac{40 + 10 i}{9 - i^{2}}$

Simplify each term.

Rewrite $i^{2}$ as $- 1$ .

$\frac{40 + 10 i}{9 - - 1}$

Multiply $- 1$ by $- 1$ .

$\frac{40 + 10 i}{9 + 1}$

Add $9$ and $1$ .

$\frac{40 + 10 i}{10}$

Step 3

Cancel the common factor of $40 + 10 i$ and $10$ .

Factor $10$ out of $40$ .

$\frac{10 \cdot 4 + 10 i}{10}$

Factor $10$ out of $10 i$ .

$\frac{10 \cdot 4 + 10 (i)}{10}$

Factor $10$ out of $10 (4) + 10 (i)$ .

$\frac{10 (4 + i)}{10}$

Cancel the common factors.

Factor $10$ out of $10$ .

$\frac{10 (4 + i)}{10 (1)}$

Cancel the common factor.

$\frac{10 (4 + i)}{10 \cdot 1}$

Rewrite the expression.

$\frac{4 + i}{1}$

Divide $4 + i$ by $1$ .

$4 + i$

Write in Standard Form (13-i)/(3-i)

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